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Statistical Mechanics$\Rightarrow$}Blackbody Radiation Formula

The blackbody radiation formula has $u=\sigma T^4$. The ratio of energy radiated is thus $T_2^4/T_1^4$. Since $T_2=3T_1$, the ratio is just $3^4=81$, as in choice (E). (Obviously an increase since the final temperature is much higher than the initial.)

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