GR0177 #68



Alternate Solutions 
jmason86 20090714 22:32:55  The quickthinking, timepressure solution that I did was:
(A) decay would change the atomic number nucleon number from 7.
decay explains the p>n transformation but requires two particles to be emitted (e+/e and /bar)
(B) (C) (D) do not satisfy this
Only (E) remains. Electron capture is also basically an odd form of beta decay.. all the particles involved are the same, the equation just changes a bit.  

Comments 
sam16 20151022 07:46:52  The electron capture process also emits a neutrino. I don\'t see how one can guess between electron capture and beta decay in that case...\r\n\r\nSource http://hyperphysics.phyastr.gsu.edu/hbase/nuclear/radact2.html
sam16 20151022 07:48:52 
Edit: The options specify that explicitly. My bad!

  berri104 20131014 07:57:10  I am confused by this notation. Isn't the mass number A at the top while the atomic number Z (the number of protons) on the bottom? And how does losing a proton amount to losing a neutrino?   Kabuto Yakushi 20100910 21:30:31  Five particle interaction conservation laws that would probably be a good idea to memorize for this test:
1) Charge is conserved.
2) Energy is conserved.
3) Lepton number is conserved separately for each family.
4) Baryon number is conserved.
5) Strangeness is conserved for strong interaction.
As Yosun said, we see that E) is the only one that does not violate the third conservation law.   jmason86 20090714 22:36:23  Sorry that was sloppy. Here it is again:
The quickthinking, timepressure solution that I did was:
(A) decay would change the nucleon number from 7.
decay explains the p>n transformation but requires two particles to be emitted (e+/e and /bar)
(B) (C) (D) do not satisfy this
Only (E) remains. Electron capture is also basically an odd form of beta decay.. all the particles involved are the same, the equation just changes a bit.
  jmason86 20090714 22:32:55  The quickthinking, timepressure solution that I did was:
(A) decay would change the atomic number nucleon number from 7.
decay explains the p>n transformation but requires two particles to be emitted (e+/e and /bar)
(B) (C) (D) do not satisfy this
Only (E) remains. Electron capture is also basically an odd form of beta decay.. all the particles involved are the same, the equation just changes a bit.   Poop Loops 20081101 20:25:10  I did this by process of elimination since a particle class is only offered spring quarter senior year at my school...
So:
(A) Alpha particle is a helium nucleus. This won't get us anywhere because helium has 2 protons and we are only dropping our Z (number of protons) by one.
(B) This will simply ionize the particle, so it will still be Be, but with a positive charge. No good.
(C) This will lower the mass, but our mass stays constant here. Further, this won't lower the Z number. Nope.
(D) A positron is the antiparticle of the electron. It is exactly like the electron except it has positive charge. You don't get these in runofthemill atoms, so you can throw this away. But, even if you weren't sure, you can still tell that the Z number won't go down because that refers specifically to protons.
(E) Eh? I don't know what this is. Sure, let's go with this. The little bit I do know says that Neutrons are Protons and Electrons combined together, so that helps.   abby 20071029 10:26:09  isn't an alpha particle a helium atom with 2neutrons and 2protons? why does the answer say 4neutrons.. (typo?)
mrbojeebers 20071029 22:25:21 
Appears to be a typo. Perhaps it was meant 4 nucleons. And not to be a stickler over niggling details, but traditionally one denotes the atomic number with letter and mass or nucleon number with letter (i.e. the symbols and are typically swapped in your decay equations.)

 

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