GR9277 #55



Alternate Solutions 
h.fei10 20121104 05:11:22  The force should be proportional to the length b, remember the formula F=BIL in high school, so eliminate A,B,E.
The force is related to r, so only D remains.   jmason86 20090906 16:13:03  lots of solutions up here already but...
There's no reason that ln should come into this calculation. Eliminate (A) and (B)
As other have said, as r> F>0. Eliminates (C) and (E)  

Comments 
emmo 20191218 06:28:15  According to this solution, \"the crossproduct yields 0 force for the two horizontal components,\" but is that right? The field is pointing into the page, which is orthogonal to the line of the induced current, thus there would be force on each horizontal component. This contributes nothing to the net force due to symmetry: the top and bottom horizontal portions of the induced current cancel one another out.   h.fei10 20121104 05:11:22  The force should be proportional to the length b, remember the formula F=BIL in high school, so eliminate A,B,E.
The force is related to r, so only D remains.   pkamal 20101008 09:16:55  Here is one more way of looking at this problem.
In the limit a>0, the net force on the wire must be zero, because you will have two equal and opposite forces acting on the wire. So, the only choice that goes to zero in the limit a>0 is D. So D is the correct choice:)
neon37 20101112 00:56:42 
incorrect. Also, A and B go to zero as ln(1)=0. This works only if you eliminate A and B first.

  pkamal 20101008 09:16:21  Here is one more way of looking at this problem.
In the limit a>0, the net force on the wire must be zero, because you will have two equal and opposite forces acting on the wire. So, the only choice that goes to zero in the limit a>0 is D. So D is the correct choice:)   Fortisimo 20101005 12:52:47  C, D, E should not have the natural logs; this appears to be a typo   jmason86 20090906 16:13:03  lots of solutions up here already but...
There's no reason that ln should come into this calculation. Eliminate (A) and (B)
As other have said, as r> F>0. Eliminates (C) and (E)
RusFortunat 20151022 18:10:05 
Thank you

  neutrinosrule 20081004 17:36:00  you can just note that the force has to be inversely proportional to the distance from the loop to the wire... this only leaves D.   spacebabe47 20070828 14:55:13  there is no ln in answers C,D,and E   bootstrap 20070406 12:51:52  An easy way to do this without paying too much attention to the different forces is looking at the solutions as the limit of r goes to infinity. The only answer that clearly goes to zero is choice D.
hassanctech 20070930 21:16:47 
That isn't true. In choices a and b the ln(r/(r+a)) and ln ((r+a)/r) both go to ln(1) as r > infinity and ln(1) = o so choices 1 and 2 also go to zero.

  spacebabe47 20061101 15:13:59  If the area of the loop is zero, there will be no flux, and hence no induced current and no force. So, F=0 if a=0. This eliminates A, B, and C. Also, F=0 if b=0. This eliminates E. Only choice D is left.
spacebabe47 20061101 15:23:30 
Edit:
If the area of the loop is zero, there will be no flux, and hence no induced current and no force. So, F=0 if a=0. This eliminates C. Also, F=0 if b=0. This eliminates A, B, and E. Only choice D is left.

  senatez 20061031 20:47:42  You can also consider the limiting case where the force will go to zero as r goes to zero. This will eliminate choices C and E. From here you can make an educated guess. One would expect the force to depend on both dimensions a and b. So then chose choice D.  




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